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| © AIMCO, 2001 |
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Increased Productivity
Means Increased Profits |
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Provide a faster cycle time per fastener
- One hand operation
- Reduce number of steps
- Reduce wasted time or downtime
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SAVE TIME PER WORKPIECE |
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This reduces your labor content per workpiece.
This enables the manufacturer to lower their price or increase their profit
margins.
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PAYBACK: Multiply the time
savings per workpiece times the number of pieces in a year. Multiply
the time savings per year by the overhead or labor cost per hour to get your
yearly cost savings. Divide the investment cost for your solution by
the yearly cost savings. This is your payback in time in years.
Many companies strive for a payback period of less than 1.5 years or 18
months.
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(time saved per piece)
(yearly time savings)
(solution costs) |
X
X
/ |
(pieces per year)
(overhead hourly cost)
(yearly cost savings) |
=
=
=
= |
yearly time savings
yearly cost savings
payback time in years
less than 1.5 years or 18 months |
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ASSEMBLE MORE WORK PIECES PER TIME PERIOD |
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The manufacturer can produce more products to
sell. This may reduce their labor cost per unit, but also increases
their profit per day.
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PAYBACK: There are two steps
here. For the time savings, multiply the time savings per workpiece
times the number of pieces in a year. Multiply the time savings per
year by the overhead or labor cost per hour to get your yearly cost savings.
For the increased profit, multiply the increased number of pieces per year
times the approximate profit per item. Add these two dollar amounts
together. Lastly, divide the investment cost for your solution by the
yearly total savings. This is your payback time in years. Many
companies strive for a payback period of less than 1.5 years or 18 months.
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TIME SAVINGS: |
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(time saved per piece)
(yearly time savings)
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X
X |
(pieces per year)
(overhead hourly cost) |
=
= |
yearly time savings
yearly cost savings |
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INCREASED PROFIT: |
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(increased product per year)
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X |
(approx profit per product) |
= |
yearly additional profit |
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TOTAL SAVINGS: |
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(yearly cost savings)
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+ |
(yearly additional profit) |
= |
yearly total savings |
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PAYBACK TIME: |
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(solution costs)
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/ |
(yearly total savings) |
= |
payback time in years |
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EXAMPLE |
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A ULT-70 pulse tool saves 2 seconds per
fastener on a product with four fasteners per piece. They make 20
pieces an hour, 2 shifts per day, at an overhead cost of $25 per hour.
The pulse tool costs about $2,000.
TIME SAVED PER PIECE = 2 sec X 4 X 20 X 16 X 200 day/year X 1 hr/3,600
seconds =
142 hours saved X $25/hour = $3,555 yearly savings
PAYBACK TIME = $2,000 / $3,555 = 0.56 years
or under 7 months.
This means that the purchase of the
pulse tool will pay for itself in less than 7 months!
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WHO IS INVOLVED WITH PRODUCTIVITY? |
- Production management and operators
- Production or manufacturing engineers
- Purchasing
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